[XSL-LIST Mailing List Archive Home] [By Thread] [By Date]

Re: [xsl] Updating Attribute Values


Subject: Re: [xsl] Updating Attribute Values
From: Nathan Tallman <ntallman@xxxxxxxxx>
Date: Fri, 16 Aug 2013 09:27:41 -0400

Thank you everyone for your comments. They gave me the clue I needed.
The below code is working for my situation, which transforms an
existing XML by updating dao[@href].

<xsl:template match="dao[@href]">
            <xsl:copy>
                <xsl:copy-of select="@*"/>
                <xsl:apply-templates />
                <xsl:attribute name="href">
                    <!-- do stuff -->
                </xsl:attribute>
            </xsl:copy>
    </xsl:template>

Nathan

On Thu, Aug 15, 2013 at 11:25 AM, David Carlisle <davidc@xxxxxxxxx> wrote:
> On 15/08/2013 15:41, Nathan Tallman wrote:
>>
>> I'd like to change the values of attribute "href", whenever it appears
>> inside a "dao" element. From what I can tell, my template is correct,
>> however when ever I stick anything inside xsl:attribute (replace <!--
>> do stuff here -->, nothing happens during the transformation. Am I
>> missing something?
>>
>>      <xsl:template match="@href[parent::dao]">
>>          <xsl:attribute name="href">
>>              <!-- do stuff here -->
>>          </xsl:attribute>
>>      </xsl:template>
>>
>> I'm using XSLT 2.0, Saxon 6.5.5.
>>
>> Thanks,
>> Nathan
>
>
>
> In addition to the other comments re XSLT version and namespaces, a template
> matching an attribute only does anything if you apply templates to that
> attribute. The default processing does not do that:
>
> <xsl:template match="dao">
> ... stuff..
> <xsl:apply-templates/>
> ..
> </xsl:template>
>
> would apply templates to child nodes of <dao> but not to its attributes.
>
> David


Current Thread
Keywords