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Re: [xsl] Determining the type of items in a sequence

Subject: Re: [xsl] Determining the type of items in a sequence
From: "G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx>
Date: Mon, 11 Mar 2013 18:40:08 -0400

Actually, to ensure there is at least one node it would be:

instance of node()+

. . . . . . Ken

At 2013-03-11 18:36 -0400, I wrote:
At 2013-03-11 18:31 -0400, Wendell Piez wrote:
Could someone please remind me the most graceful way in XPath 2.0 of
determining dynamically whether any arbitrary $n is bound to a node or
sequence of nodes (i.e., no atomic values)?

instance of node()*

There's some furious parameterization going on and I just can't
remember this. (It's not the kind of thing easy to search for either.)

Not sure what you are referring to regarding parameterization.

I hope the illustration below helps.

. . . . . . . . Ken

t:\ftemp>type wendell.xsl
<?xml version="1.0" encoding="US-ASCII"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"

<xsl:output method="text"/>

<xsl:template match="/">
  <xsl:variable name="test1" select="doc(''),doc('')/*/xsl:*"/>
  <xsl:value-of select="count($test1),$test1 instance of node()*,'&#xa;'"/>
  <xsl:variable name="test2" select="$test1,'hello',$test1"/>
  <xsl:value-of select="count($test2),$test2 instance of node()*,'&#xa;'"/>

t:\ftemp>xslt2 wendell.xsl wendell.xsl
3 true
7 false


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