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[xsl] Why doesn't copy xmlns=""?


Subject: [xsl] Why doesn't <xsl:copy> copy xmlns=""?
From: "Costello, Roger L." <costello@xxxxxxxxx>
Date: Sat, 17 Nov 2012 13:39:20 +0000

Hi Folks,

I want to do an identity transform of this:
----------------------------------------------------------------------------
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema"
           	       targetNamespace="http://www.bar.com"
           	        xmlns:bar="http://www.bar.com"
           	        xmlns=""
           	        elementFormDefault="qualified">

    ...

</xs:schema>
----------------------------------------------------------------------------

Notice the default namespace declaration, xmlns=""

Here is the code that I use to do the identity transform:

    <xsl:template match="xs:schema">
        <xsl:copy>
            <xsl:copy-of select="@*" />
            <xsl:sequence select="node() | comment() |
processing-instruction()" />
        </xsl:copy>
    </xsl:template>

(I use this code because I actually do more than just an identity transform,
which I do not show here.)

Here is the output from transforming the <xs:schema> with my code:
----------------------------------------------------------------------------
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema"
           	       targetNamespace="http://www.bar.com"
           	        xmlns:bar="http://www.bar.com"
           	        elementFormDefault="qualified">

    ...

</xs:schema>
----------------------------------------------------------------------------

Yikes!

What happened to the default namespace declaration?

Questions:

1. Why is my code not copying over the default namespace declaration?

2. What change can I make to my code to ensure that it copies over the default
namespace declaration?

/Roger


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