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Dear list,
I have an XPath question to which I cannot find the answer.
Let $node_set be a set of element nodes, stored in a variable. In this set there is an element with @id="foo". I would like to know the position of this element within the node set. I found the following solution:
I cannot but think that there is a quicker, XPath-only solution to this, yet I cannot find it. Thank you for your help!
Wolfhart
[xsl] finding the position of a node within a node set
Subject: [xsl] finding the position of a node within a node set From: Wolfhart Totschnig <wolfhart@xxxxxxxxxxxxx> Date: Sun, 26 Aug 2012 00:41:55 -0500 |
Dear list,
I have an XPath question to which I cannot find the answer.
Let $node_set be a set of element nodes, stored in a variable. In this set there is an element with @id="foo". I would like to know the position of this element within the node set. I found the following solution:
<xsl:for-each select="$node_set"> <xsl:if test="@id='foo'"> <xsl:value-of select="position()"> </xsl:if> </xsl:for-each>
I cannot but think that there is a quicker, XPath-only solution to this, yet I cannot find it. Thank you for your help!
Wolfhart
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