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Re: AW: [xsl] XPath question concerning distinct-values()


Subject: Re: AW: [xsl] XPath question concerning distinct-values()
From: Thorsten <xsl-list@xxxxxxxxxxxxx>
Date: Fri, 3 Aug 2012 13:37:49 +0200 (CEST)

Hi Patrick,

the xsl:if statement works fine.
Thanks a lot!


Regards
Thorsen


"Szabo, Patrick (LNG-VIE)" <patrick.szabo@xxxxxxxxxxxxx> hat am 3. August
2012
um 13:26 geschrieben:> Actually just checking for a preceding item with the
same
order-number would probably suffice.
>
> <xsl:template match="item">
> <xsl:if test="not(preceding-sibling::item[order-number =
> current/oder-number])">
> <xsl:value-of select="concat(order-number, ' ', price)">
> </xsl:if>
> </xsl:template>
>
>
> . . . . . . . . . . . . . . . . . . . . . . . . . .
> Developer Patrick Szabo
> Developer
> LexisNexis
> A-1030 Wien, Marxergasse 25
>
> mailto:patrick.szabo@xxxxxxxxxxxxx
> Tel.: +43 1 53452 1573
> Fax: +43 1 534 52 146
>
>
> -----UrsprC<ngliche Nachricht-----
>
> Von: Szabo, Patrick (LNG-VIE) [mailto:patrick.szabo@xxxxxxxxxxxxx]
> Gesendet: Freitag, 03. August 2012 13:22
> An: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Betreff: AW: [xsl] XPath question concerning distinct-values()
>
> Hi,
>
> You could still use distinct-values and then "iterate" those values and
output
> the desire values from the first item you find with the corresponding
> order-number.
>
> Something like
>
> <xsl:for-each select="distinct-values(/pricelist/item) ">
> <xsl:value-of
>
select="concat(/pricelist/item/order-number[parent::item[order-number=.][1]],
> ' ', /pricelist/item/price[parent::item[order-number=.][1]])">
> </xsl:for-each>
>
> There's probably a more elegant way to do it tough.
>
> Best regards
>
>
> . . . . . . . . . . . . . . . . . . . . . . . . . .
> Developer Patrick Szabo
> Developer
> LexisNexis
> A-1030 Wien, Marxergasse 25
>
> mailto:patrick.szabo@xxxxxxxxxxxxx
> Tel.: +43 1 53452 1573
> Fax: +43 1 534 52 146
>
>
> -----UrsprC<ngliche Nachricht-----
>
> Von: Thorsten [mailto:xsl-list@xxxxxxxxxxxxx]
> Gesendet: Freitag, 03. August 2012 13:14
> An: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Betreff: [xsl] XPath question concerning distinct-values()
>
> Hello,
>
> I have a terrible SAP export that looks (simplified) like this:
>
> <pricelist>
> <item>
> <title>Lorem Ipsum Dolor Sit Amet</title>
> <order-number>XY7020280901</order-number>
> <price>12.00</price>
> <unit>50</unit>
> </item>
> <item>
> <title>Some Title</title>
> <order-number>XY9010200901</order-number>
> <price>19.00</price>
> <unit>50</unit>
> </item>
> <item>
> <title>The Same Item With A Different Title</title>
> <order-number>XY9010200901</order-number>
> <price>19.00</price>
> <unit>50</unit>
> </item>
> <item>
> <title>Lorem Ipsum Dolor</title>
> <order-number>XY7010220201</order-number>
> <price>18.00</price>
> <unit>50</unit>
> </item>
> </pricelist>
>
> I want to select each <item> with different <order-number>. Simply
> distinct-values(/pricelist/item) doesn't work because the <title> of
item[2]
> and
> item[3] are different.
>
> My output should look like this:
> XY7020280901 12.00
> XY9010200901 19.00
> XY7010220201 18.00
>
> I'm using XSLT2.0 with Saxon 9.2 PE.
>
> Any ideas?
>
> Many thanks in advance.
>
> Kind regards
> Thorsten


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