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Re: [xsl] shortest way to write this xsl:if statement
Subject: Re: [xsl] shortest way to write this xsl:if statement From: henry human <henry_human@xxxxxxxx> Date: Fri, 15 Jun 2012 13:36:10 +0100 (BST) |
Now the problem is, the loop bellow of xsl:if is only one time created but I have more findings in the if statement regarding A, B, C, D (founds at least 4 times because D4/G100/6id = 'A' , D4/G100/9id = 'B' , D4/G100/10id = 'C' , D4/G100/11id ='D') => the code bellow of the xsl:if statemnt should be repeated as much as if statement find A, B, C, D,.. ----- Urspr|ngliche Message ----- Von: G. Ken Holman <gkholman@xxxxxxxxxxxxxxxxxxxx> An: xsl-list@xxxxxxxxxxxxxxxxxxxxxx; "xsl-list@xxxxxxxxxxxxxxxxxxxxxx" <xsl-list@xxxxxxxxxxxxxxxxxxxxxx> CC: Gesendet: 13:59 Freitag, 15.Juni 2012 Betreff: Re: [xsl] shortest way to write this xsl:if statement At 2012-06-15 12:54 +0100, henry human wrote: > Hello > The following if statement is too long if try it as in the sample bellow. > How could be shorter? > The if - logic to create a for-each loop: > ---------------- > xsl:if > D4/G100/6id or D4/G100/9id or D4/G100/12id or D4/G100/6id15 or D4/G100/45id or D4/G100/22id, D4/G100/10id > or D4/G100/19id is 'A' or 'B' or 'C', or 'D' or 'F' > > The Sample: > <xsl:if test="D4/G100/6id = 'A' OR test="D4/G100/6id = 'B' OR test="D4/G100/6id = 'C' OR test="D4/G100/9id = 'A' OR test="D4/G100/9id = 'B' .....> > > <xsl:for-each select=" ......"> > ... > </xsl:for-each> > > </xsl:if> Element names cannot begin with digits, so I'm unclear how you are going to be testing elements such as <6id>. But, assuming you had elements D4/G100/X and D4/G100/Y and D4/G100/Z, you could have in XSLT2 the following: <xsl:if test="D4/G100/(X,Y,Z) = ('A','B','C')"> ... which is equivalent to: D4/G100/X = 'A' or D4/G100/X = 'B' or D4/G100/X = 'C' or D4/G100/Y = 'A' or D4/G100/Y = 'B' or D4/G100/Y = 'C' or D4/G100/Z = 'A' or D4/G100/Z = 'B' or D4/G100/Z = 'C' When using the "=" comparison operator, either operand can be a set. The processor walks through the comparisons in an arbitrary order eventually testing each of the left operand with each of the right operand and stops when it hits a true() result and returns true(). If you get a false() returned, you know the processor has checked every possible combination and every combination has returned false(). I hope this helps. . . . . . . . . . . . Ken -- Public XSLT, XSL-FO, UBL and code list classes in Europe -- Oct 2012 Contact us for world-wide XML consulting and instructor-led training Free 5-hour lecture: http://www.CraneSoftwrights.com/links/udemy.htm Crane Softwrights Ltd. http://www.CraneSoftwrights.com/s/ G. Ken Holman mailto:gkholman@xxxxxxxxxxxxxxxxxxxx Google+ profile: https://plus.google.com/116832879756988317389/about Legal business disclaimers: http://www.CraneSoftwrights.com/legal
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