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Re: [xsl] Get the first Array element
Subject: Re: [xsl] Get the first Array element From: henry human <henry_human@xxxxxxxx> Date: Fri, 11 May 2012 12:24:27 +0100 (BST) |
If I have it in this way in the otherwise part I get for that Taxtotal which HAS NO Amount still a result (<amount>00000000000000</amount>) Therfore I did : <xsl:otherwise></xsl:otherwise> The solution works fine for me, thnak you guys! But I think still this statement : <xsl:when test="cac:TaxTotal[child::cbc:Amount][1]/cbc:Amount does not query ONLY the taxtotal elemnets which HAS AN amount but the other taxtotals too? Kind regards hny ----- Urspr|ngliche Message ----- Von: Michel Hendriksen <michel.hendriksen@xxxxx> An: xsl-list@xxxxxxxxxxxxxxxxxxxxxx CC: Gesendet: 12:27 Freitag, 11.Mai 2012 Betreff: Re: [xsl] Get the first Array element First test had a space it seems, so never matched So something like: (second part not needed I guess, test might better) <xsl:choose> <xsl:when test="cac:TaxTotal[child::cbc:Amount][1]/cbc:Amount >= 0"> <xsl:value-of select="format-number(floor(cac:TaxTotal[child::cbc:Amount][1]/cbc:Amount),'+ 0000000000000;-0000000000000') "/> </xsl:when> <xsl:when test="cac:TaxTotal[child::cbc:Amount][1]/cbc:Amount < 0"> <xsl:value-of select="format-number(floor(cac:TaxTotal[child::cbc:Amount][1]/cbc:Amount),'+ 0000000000000;-0000000000000') "/> </xsl:when> <xsl:otherwise>00000000000000</xsl:otherwise> </xsl:choose>
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