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[xsl] A shorter way to test for position?


Subject: [xsl] A shorter way to test for position?
From: Dan Acuff <dacuff@xxxxxxxxxxxxxx>
Date: Thu, 10 May 2012 13:58:05 +0000

Isn't there a shorter way to add a style attribute to the <div
class="cat_module"> element than doing a choose/when/otherwise like I have
done below?
This will work but if there is shorthand I want to learn it.
Help Much appreciated.

    <xsl:choose>
    <xsl:when test="position() mod 3 = 0">
      <div class="cat_module" style="border-right: none;">
      <div class="cat_image">
       <a href="{descendant::link}"><img src="{descendant::image}"
alt=""/></a>
      </div>

      <div class="cat_desc">
        <h2>
		   <a href="{descendant::link}"><xsl:value-of select="@display_name"/></a>
	 	  </h2>
  	   </div>

       <a href="{descendant::link}">
       <span>Shop Now</span>
      </a>
     </div>
    </xsl:when>
    <xsl:otherwise>
      <div class="cat_module">
        <div class="cat_image">
          <a href="{descendant::link}">
            <img src="{descendant::image}" alt=""/>
          </a>
        </div>

        <div class="cat_desc">
          <h2>
            <a href="{descendant::link}">
              <xsl:value-of select="@display_name"/>
            </a>
          </h2>
        </div>

        <a href="{descendant::link}">
          <span>Shop Now</span>
        </a>
      </div>
    </xsl:otherwise>
    </xsl:choose>


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