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Re: [xsl] position() function in loop provides only 1

Subject: Re: [xsl] position() function in loop provides only 1
From: Michael Kay <mike@xxxxxxxxxxxx>
Date: Wed, 11 Apr 2012 14:20:00 +0100

If you'd like to supply a small but complete sample source document and stylesheet, rather than incomplete fragments, then I'm sure we'll be able to tell you what's going on.

Michael Kay

On 11/04/2012 14:08, henry human wrote:
I now that the position() reset after a loop is ended and I am not expecting some thing else .
In my case the position () provides correctly the POSITION for each loop in the FIRST loop but
in the other loop (xsl:for-each select="taxtotal) the position() function provides ever ONE and does not increment!!!
Regarding number function I do not now how to use it here. and I think you are wrong, in XSLT you canbt save value to a variable and use it global!
Kind regards

----- UrsprC<ngliche Message -----
Von: Michel Hendriksen<michel.hendriksen@xxxxx>
An: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Gesendet: 14:06 Mittwoch, 11.April 2012
Betreff: Re: [xsl] position() function in loop provides only 1

In for each the context will switch, so position will be reset inside
You could keep position in a variable if you need it.


On Wed, Apr 11, 2012 at 1:57 PM, henry human<henry_human@xxxxxxxx> wrote:
Hi all
I use the positon() funciton to build a counter.
I use it in a for-each loop under another for-each. The result is but ever 1.
Strange, but in the same document in the first for-each loop it works fine (bellow is first loop, for-each select="Item)
sample document look like this:

<xsl:for-each select="Item"> <it> <xsl:value-of select=" position()">

<xsl:value-of select=" position()">
//position  = 113
<xsl:for-each select="InvoiceLine">
    <xsl:for-each select="taxtotal">
<xsl:value-of select=" position()">


kind regards

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