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Re: [xsl] __LINE__ equivalent in XSLT

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Sorry,

this

(line 34)<xsl:comment>line <xsl:value-of  select="saxon:line-number()"/>

gives this

<!--line -1

Many thanks

Bye

Il giorno ven, 02/12/2011 alle 16.01 +0100, Bartolomeo Nicolotti ha
scritto:
> hello,
> 
> I've tried this:
> 
> zxsl:value-of select="saxon:line-number(.)"/>
> </xsl:template>
> 
> buy gives me the line of the input xml
> 
> I need to know the line number in the xslt itself
> 
> Many thanks
> 
> Bye
> 
> Il giorno ven, 02/12/2011 alle 13.01 +0000, Michael Kay ha scritto:
> > You could implement the preprocessor easily enough if you are using 
> > Saxon. For example if you use <?line?> then you can write the 
> > preprocessor as
> > 
> > <xsl:template match="*">
> >    .. identity template ..
> > </xsl:template>
> > 
> > <xsl:template match="processing-instruction(line)">
> > <xsl:value-of select="saxon:line-number(.)"/>
> > </xsl:template>
> > 
> > Michael Kay
> > Saxonica
> > 
> > On 02/12/2011 12:14, Bartolomeo Nicolotti wrote:
> > > To whom it may concern,
> > >
> > > in C there's a pre-processor directive
> > >
> > > __LINE__
> > >
> > > that gives you the line of source where the directive is.
> > >
> > > Is there an equivalent in XSLT?
> > >
> > > Many thanks
> > >
> > > Best regards
> > >
> > > Bartolomeo

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