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At 2011-11-22 18:22 +0100, Martin Honnen wrote:
Whenever I have the expression "if ( x ) then x else y" and x is a node, as can be used in this example, I use:
(x,y)[1]
... which in your example translates to:
group-by="number((Stamp/@line,0)[1])"
I hope this helps.
. . . . . . . . . . Ken
Re: [xsl] group-by an optional attribute
Subject: Re: [xsl] group-by an optional attribute From: "G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx> Date: Tue, 22 Nov 2011 13:03:03 -0500 |
At 2011-11-22 18:22 +0100, Martin Honnen wrote:
Mark wrote:
I tried to formulate an alternative, thinking this would group-by the true value of @line were it present, or by zero in its absence, but it fails: <xsl:for-each-group select="current-group()" group-by="if(Stamp/@line) then Stamp/@line else 0">
Can you post details as to why exactly this fails? Do you get an error? Does group-by="if (Stamp/@line) then number(Stamp/@line) else 0" work better?
Whenever I have the expression "if ( x ) then x else y" and x is a node, as can be used in this example, I use:
(x,y)[1]
... which in your example translates to:
group-by="number((Stamp/@line,0)[1])"
I hope this helps.
. . . . . . . . . . Ken
-- Contact us for world-wide XML consulting and instructor-led training Free 5-hour video lecture: XSLT/XPath 1.0 & 2.0 http://ude.my/t37DVX Crane Softwrights Ltd. http://www.CraneSoftwrights.com/s/ G. Ken Holman mailto:gkholman@xxxxxxxxxxxxxxxxxxxx Google+ profile: https://plus.google.com/116832879756988317389/about Legal business disclaimers: http://www.CraneSoftwrights.com/legal
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