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Re: [xsl] Can a single XPath statement duplicate the functionality of this verbose statement?

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At 2011-10-23 17:58 -0700, Mark wrote:

Hi Ken,
I removed the [1] at the end to get all of the returns, and for the second example a '50' is returned, the @denomination[5] and the default [0]. It is clear that the @souvenir-sheet value is ignored in both cases. I am using XSLT 2, so it always collapses. Is there something incorrect with

../Location[name(@*)=name(current()/@*)]

It seems correct to me.

You are addressing the element and I copied that without thinking. I think you only want the attribute:

../Location/@*[name(.)=name(current()/@*)]

. . . . . . . . . . Ken

Mark

-----Original Message----- From: Mark
Sent: Sunday, October 23, 2011 5:39 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: [xsl] Can a single XPath statement duplicate the functionality of this verbose statement?

Hi Ken,
Yes, only one attribute to either element.

You said:
xsl:copy-of select="( ../Location[name(@*)=name(current()/@*)] ,
                    ../Location/@denomination ,
                    '0' )[1]"/>

but I may have explained my needs incorrectly. Your statement works on the
first example below [uses @denomination] but returns nothing for the second
example; there it should return the value of the <Locations
@souvenir-sheet>, i.e., '1'.
Thanks,
Mark

<Stamp>
       <Formats souvenir-sheet="2895"/>
     <Location denomination="1"/>
</Stamp>

<Stamp>
      <Formats souvenir-sheet="2896"/>
     <Location denomination="5"/>
     <Location souvenir-sheet="1"/>
   </Stamp>

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