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Re: [xsl] basename string sort and group


Subject: Re: [xsl] basename string sort and group
From: Martin Honnen <Martin.Honnen@xxxxxx>
Date: Sat, 03 Sep 2011 14:10:28 +0200

davep wrote:
Given input such as
<fonts>
<entry
href="/apps/jdk/lib/fonts/LucidaTypewriterRegular.ttf">Lucida</entry>
<entry href="/apps/jdk/lib/fonts/LucidaTypewriterBold.ttf">Lucida</entry>
<entry
href="/apps/jdk/lib/oblique-fonts/LucidaSansDemiOblique.ttf">Lucida</entry>
</fonts>

I want to sort and group by directory, for an output such as

<fonts>
<dir href="/apps/jdk/lib/fonts">
<entry href="LucidaTypewriterRegular.ttf">Lucida</entry>
<entry href="LucidaTypewriterBold.ttf">Lucida</entry>
</dir>
<dir href="/apps/jdk/lib/oblique-fonts">
<entry href="LucidaSansDemiOblique.ttf">Lucida</entry>
</dir>

etc.

I.e. Isolate the directories, then group all entries within that directory.


<xsl:template match="fonts">
<xsl:copy>
<xsl:for-each-group select="entry"
group-by="string-join(tokenize(@href, '/')[position() lt last()], '/')>
<dir href="{current-grouping-key()}">
<xsl:apply-templates select="current-group()"/>
</dir>
</xsl:for-each-group>
</xsl:copy>
</xsl:template


   <xsl:template match="entry">
     <entry href="{tokenize(@href, '/')[last()]}">
        <xsl:value-of select="."/>
     </entry>
   </xsl:template>

Untested.


--


	Martin Honnen --- MVP Data Platform Development
	http://msmvps.com/blogs/martin_honnen/


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