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Thanks for the fast reply! But deep-equal is not an XSLT 1.0 function. The script will be processed by a browser (Firefox), and so I have to remain within XSLT 1.0.
Wolfhart
Robby Pelssers wrote:
Re: [xsl] compare two nodes (the child elements, not the string values) in XSLT 1.0
Subject: Re: [xsl] compare two nodes (the child elements, not the string values) in XSLT 1.0 From: Wolfhart Totschnig <wolfhart@xxxxxxxxxxxxx> Date: Wed, 06 Jul 2011 14:15:38 -0500 |
Thanks for the fast reply! But deep-equal is not an XSLT 1.0 function. The script will be processed by a browser (Firefox), and so I have to remain within XSLT 1.0.
Wolfhart
Robby Pelssers wrote:
http://www.w3.org/TR/xpath-functions/#func-deep-equal
-----Original Message-----
From: Robby Pelssers [mailto:Robby.Pelssers@xxxxxxx] Sent: Wednesday, July 06, 2011 8:57 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: RE: [xsl] compare two nodes (the child elements, not the string values) in XSLT 1.0
Try the deep-equal function... Robby
-----Original Message-----
From: Wolfhart Totschnig [mailto:wolfhart@xxxxxxxxxxxxx] Sent: Wednesday, July 06, 2011 8:55 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: [xsl] compare two nodes (the child elements, not the string values) in XSLT 1.0
Hello,
I have a seemingly simple xslt problem to which I cannot find the solution. I want to test whether the context node, which is an <author> element with the form (first?, middle?, last), is equal to one of a set of <person> elements. By "equal" I mean having the same child elements and values of these elements. At first, I thought it would be as easy as
test="path/person = ."
But then I realized that the "=" operator compares the string values of the nodes, such that
<author> <first>John</first> <last>Doe</last> </author>
and
<person> <last>JohnDoe<last> </person>
will be evaluated as equal, which I want to avoid. So how can I check, in XSLT 1.0, whether two nodes are equal in the sense I intend?
Thank you for your help! Wolfhart
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