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Re: [xsl] replacing nodes during xsl:copy-of

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> From a high-level, non-technical, viewpoint, what I need to do is convert
the XML to HTML  and either during the process, or after replace everything in
the <replace> elements with something else.

Ok this is your starting point - its an "identity transform" which
copies the input to the output node by node.  The more specific
template which matches the "replace" element takes precedence over the
"identity template":

<xsl:stylesheet version="2.0"
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:xs="http://www.w3.org/2001/XMLSchema"
    exclude-result-prefixes="xs">

<xsl:template match="@*|node()">
	<xsl:copy>
		<xsl:apply-templates select="@*|node()"/>
	</xsl:copy>
</xsl:template>

<xsl:template match="replace">
  [ something else ]
</xsl:template>

</xsl:stylesheet>

If you run that transform on this input:

<foo>hello <replace>world</replace></foo>

you get this output:

<foo>hello
  [ whatever ]
</foo>






--
Andrew Welch
http://andrewjwelch.com

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