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Re: [xsl] Syntax on XML parser?
Subject: Re: [xsl] Syntax on XML parser? From: Jack Bush <netbeansfan@xxxxxxxxxxxx> Date: Thu, 2 Dec 2010 04:28:28 -0800 (PST) |
Thanks Michael for clarifying the differences between a parser & transformation,B andB the functionality Saxon provide. So what is the default parser when using SAXBuilder(false) without specifying a parser? Thanks again, Jack ----- Original Message ---- From: Michael Kay <mike@xxxxxxxxxxxx> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Sent: Thu, 2 December, 2010 8:21:50 PM Subject: Re: [xsl] Syntax on XML parser? Saxon is an XSLT processor, not an XML parser. So you can't instantiate Saxon as a SAXBuilder. You can instantiate Saxon as a JAXP TransformerFactory: for Saxon-HE the class name is net.sf.saxon.TransformerFactoryImpl. But since JAXP doesn't have support for XSLT 2.0 features, I would encourage you to use Saxon's s9api interface instead. Michael Kay Saxonica On 02/12/2010 07:30, Jack Bush wrote: > Hi All, >B What is the syntax to reference Saxon (9.1) parser when reading XML document? > Below is an example when using Xerces parser: > cB B SAXBuilder builder = new SAXBuilder("org.apache.xerces.parsers.SAXParser", > false); >B Also like to find out what is the default parser used by JAXP such as the > following: >B B B B SAXBuilder builder = new SAXBuilder(false); >B Thanks, > Jack > > > > > --~------------------------------------------------------------------ > XSL-List info and archive:B http://www.mulberrytech.com/xsl/xsl-list > To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/ > or e-mail:<mailto:xsl-list-unsubscribe@xxxxxxxxxxxxxxxxxxxxxx> > --~--
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