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Rather than cluttering a stylesheet with conditional logic to handle two different input variants, it's almost always better to configure a pipeline in which you first (where necessary) convert the less common variant to the more common, and then do the real transformation work on normalized input.
One benefit is that the "normalizing" stylesheet is highly re-usable.
On 16/11/2010 17:33, ac wrote:
Re: [xsl] with or without namespace
Subject: Re: [xsl] with or without namespace From: Michael Kay <mike@xxxxxxxxxxxx> Date: Tue, 16 Nov 2010 19:50:41 +0000 |
Rather than cluttering a stylesheet with conditional logic to handle two different input variants, it's almost always better to configure a pipeline in which you first (where necessary) convert the less common variant to the more common, and then do the real transformation work on normalized input.
One benefit is that the "normalizing" stylesheet is highly re-usable.
Michael Kay Saxonica
On 16/11/2010 17:33, ac wrote:
Hi,
I have a xslt2 stylesheet that transforms to (x)html, an XML document type that comes in two flavors, both with the same "local-name" elements, but with or without namespace.
For example, either:
... xmlns:xx="aaa.cc"> <xx:a> <xx:b>bla</xx:b> </xx:a> ...
or
...> <a> <b>bla</b> </a> ...
To process these elements irrespective of their namespace, I can use expressions like
*[local-name(.) = "a"] and *[local-name(.) = "b"]
all through the stylesheet but, in the stylesheet, I would much rather map everything to the same namespace (possibly to default- or no-namespace) and either use a single prefix, or better still, no prefix, all over the stylesheet, to refer to all or any of these elements.
/xx:a, /xx:b, or /a , /b, for example
What would be the best way to declare the stylesheet namespaces to achieve this, if possible?
Thank you, ac
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