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Re: [xsl] replacing of characters based on position

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well, i am using xslt 2.0. i need the position based replacement rather than
regexp.
         The reason is i want reverse back  '0' with -  later at some
point , so thaat i can guarente that same uuid is going to be generated after
reversal.

step1:550e8400-e29b-41d4-a716-446655440000 to
550e84000e29b041d40a7160446655440000
step2:550e84000e29b041d40a7160446655440000   to
550e8400-e29b-41d4-a716-446655440000 

--- On Tue, 16/11/10, David Carlisle
<davidc@xxxxxxxxx> wrote:

> From: David Carlisle <davidc@xxxxxxxxx>
>
Subject: Re: [xsl] replacing of characters based on position
> To:
xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Cc: "ram" <ram_kurra@xxxxxxxxxxx>
> Date:
Tuesday, 16 November, 2010, 4:40 AM
> On 15/11/2010 22:44, ram wrote:
> > Hi,
> >         I have xsl
> variable which holds the following uuid value
>
(550e8400-e29b-41d4-a716-446655440000) which has '-' at
> 9-14-19-24
positions.
> >      I want to go these positons
> 9-14-19-24 and replace the
characters '-' with zero's.
> >       Is there any function
> such as
replace(position values,character,replace character)
> available in xslt.
> >
> > 
> > 
> you should always say whether you are using xslt 1 or 2,
>
especially if asking about string handling,
> 
> do you actually need position
based replace, (that would be
> easy using xslt 2 regexp, or only slightly
more verbose
> using a mixture of substring and concat) but your original
>
problem statement could be solved by translate(.,'-','0')
> 
> David
> 
> 
>
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