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RE: [xsl] XML attribute value to pattern match of the replace function


Subject: RE: [xsl] XML attribute value to pattern match of the replace function
From: "Selvaganesh" <selvaganesh_t@xxxxxxxxxxxxxx>
Date: Mon, 22 Feb 2010 17:36:11 +0530

Thanks Martin.

-----Original Message-----
From: Martin Honnen [mailto:Martin.Honnen@xxxxxx] 
Sent: Monday, February 22, 2010 4:54 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: [xsl] XML attribute value to pattern match of the replace
function

Selvaganesh wrote:

> 
>> You need to concat the attribute values e.g.
>>   select="replace(., concat('(', @party1, '.*?', @party2, ')'), 
>> '&lt;cite&gt;$1&lt;/cite&gt;')"
> 
> In case the xml content appear parenthesis () does not process the replace
> function can u suggest any other way.
> 
> Also I have tried below way, but does not working.
> 
> select="(concat('(', string(@party1), '.*?', string(@party2), ')'),
> '&lt;cite&gt;$1&lt;/cite&gt;')"/>
> 
> 
> Also I have tried the analyze-string method but it was working fine but
> above issue was repeated. 

Use the function defined here
http://www.xsltfunctions.com/xsl/functx_escape-for-regex.html
to escape the attribute values e.g.

<xsl:element name="caseref">
<xsl:analyze-string select="." 
regex="({functx:escape-for-regex(@party1)}.*?{functx:escape-for-regex(@party
2)})">
      <xsl:matching-substring>
         <xsl:element name="casetitle">
           <xsl:value-of select="regex-group(1)"/>
         </xsl:element>
      </xsl:matching-substring>
      <xsl:non-matching-substring>
         <xsl:value-of select="."/>
      </xsl:non-matching-substring>
    </xsl:analyze-string>
</xsl:element>
</xsl:template>

-- 

	Martin Honnen
	http://msmvps.com/blogs/martin_honnen/



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