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Re: [xsl] finding out distinct node/values


Subject: Re: [xsl] finding out distinct node/values
From: Hermann Stamm-Wilbrandt <STAMMW@xxxxxxxxxx>
Date: Wed, 10 Feb 2010 18:03:51 +0100

$ xsltproc anil.xsl anil.xml
<?xml version="1.0"?>
<name>A</name><name>B</name><name>C</name>
$ cat anil.xsl
<xsl:stylesheet version="1.0"
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform" >
  <xsl:template match="/">.
    <xsl:for-each select="/table/rows/row/name">
      <xsl:if test="not(. = preceding::name)">
        <xsl:copy-of select="."/>
      </xsl:if>
    </xsl:for-each>
  </xsl:template>
</xsl:stylesheet>
$

Mit besten Gruessen / Best wishes,

Hermann Stamm-Wilbrandt
Developer, XML Compiler, L3
WebSphere DataPower SOA Appliances
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             Anil Kumar                                                    
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                                       Re: [xsl] finding out distinct      
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Thanks Andrew for your reply. some where in the documentation I read that,

distinct-values doesn't support in XSL1.0...is that true?

>>
>> By passing the attribute "name" as a parameter, I would like to find out
the
>> all distinct values of name Attribute . i.e A,B and C
>>
>
> distinct-values(//*[name() = $name])
>
>
> cheers


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