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[xsl] creating a head-letter for directory


Subject: [xsl] creating a head-letter for directory
From: Hoskins & Gretton <hoskgret@xxxxxxxxxxxxxxxx>
Date: Mon, 18 Jan 2010 00:06:50 -0500

HI, I would like to understand, given a flat sort of data extraction, of the type
<?xml version="1.0" encoding="UTF-8"?>
<root>
<data>
<name>Aname</name>
<!-- other elements such as <location> follow, all related to the <name> -->
</data>
<data>
<name>Hname</name><!-- other elements such as <location> follow -->
</data>
<data>
<name>Dname</name><!-- other elements such as <location> follow -->
</data>
<data>
<name>Wname</name><!-- other elements such as <location> follow -->
</data>
<data>
<name>Anothername</name><!-- other elements such as <location> follow -->
</data>
<data>
<name>Whatevername</name><!-- other elements such as <location> follow -->
</data>
</root>


what are the groupings and keys needed to accomplish this (even flatter) output?

<output>
<letter>A</etter>
<name>Aname</name><!-- other elements such as <location> follow -->
<name>Anothername</name><!-- other elements such as <location> follow -->
<letter>D</etter>
<name>Dname</name><!-- other elements such as <location> follow -->
<letter>H</etter>
<name>Hname</name><!-- other elements such as <location> follow -->
<letter>W</etter>
<name>Wname</name><!-- other elements such as <location> follow -->
<name>Whatevername</name><!-- other elements such as <location> follow -->
<output>


I know that I first need to identify which first letters exist in the set of <data> elements, and then generate a <letter> element containing that first letter, followed by all the data elements children <name> that have a matching first letter. But I'm getting a <letter> element every time, rather than once for each unique occurrence, followed by the <name> elements which have a matching first letter. How do I generate the <letter> once, but follow it with all of the <name> (and related) elements? I think I need to move the <leter> element builder up out of the for-each loop that it is in, but I don't know how I then would get each letter only once for the set of all <data> elements.

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0">
<xsl:template match="/">
<xsl:variable name="blocks" select="root/data"/>
<xsl:element name="output">
<xsl:for-each-group select="$blocks" group-by="name">
<xsl:sort select="current-grouping-key()"/>
<xsl:variable name="currentGroup" select="current-grouping-key()"/>
<xsl:variable name="headletter" select="substring($currentGroup,1,1)"/>
<xsl:for-each select="."><!-- context here should be data -->
<xsl:element name="letter">
<xsl:value-of select="$headletter"/>
</xsl:element>
<xsl:apply-templates select="name[substring(.,1,1)=$headletter]"></xsl:apply-templates>
</xsl:for-each>
</xsl:for-each-group>
</xsl:element>
</xsl:template>


    <xsl:template match="name">
        <!-- is there a way that I should use the $headletter here? -->
        <xsl:element name="name"><xsl:value-of select="."/></xsl:element>
    </xsl:template>
</xsl:stylesheet>

output with duplicate <letter> values:
<?xml version="1.0" encoding="UTF-8"?>
<output>
        <letter>A</letter>
        <name>Aname</name>
        <letter>A</letter>
        <name>Anothername</name>
        <letter>D</letter>
        <name>Dname</name>
        <letter>H</letter>
        <name>Hname</name>
        <letter>W</letter>
        <name>Whatevername</name>
        <letter>W</letter>
        <name>Wname</name>
</output>

Regards, Dorothy


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