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RE: [xsl] Transforming xml with any namespace
Subject: RE: [xsl] Transforming xml with any namespace From: Anders Viklund <viklund_anders@xxxxxxxxxxx> Date: Wed, 25 Nov 2009 14:57:57 +0000 |
Ok, changed to XSLT 2.0, but still the same problem... XSL: <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0"> <xsl:output method="text" /> <xsl:template match="/"> <xsl:apply-templates/> </xsl:template> <xsl:template match="*:Type1"> <xsl:value-of select="local-name(.)"/> <xsl:text disable-output-escaping="yes">=</xsl:text> <xsl:value-of select="."/> </xsl:template> </xsl:stylesheet> OUTPUT: Type1=value1 Type1=value2 please dont print me ---------------------------------------- > Date: Wed, 25 Nov 2009 14:25:11 +0000 > From: lists@xxxxxxxxxxxx > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: Re: [xsl] Transforming xml with any namespace > > Anders Viklund wrote: > >> > > You can use the XPath 2.0 namespace wildcard: > > > > -- > Florent Georges > http://www.fgeorges..org/ > _________________________________________________________________ Keep your friends updatedeven when youre not signed in. http://www.microsoft.com/middleeast/windows/windowslive/see-it-in-action/soci al-network-basics.aspx?ocid=PID23461::T:WLMTAGL:ON:WL:en-xm:SI_SB_5:092010
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