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Jostein Austvik Jacobsen wrote:
So v1 now is a temporary document containg a deep copy of the child nodes of the content element(s). With your sample document the contents is then
and that way the template for 'note' elements outputs
So the template is applied to a copy of the original para element.
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Re: [xsl] XPath problem with getting all ancestors
Subject: Re: [xsl] XPath problem with getting all ancestors From: Martin Honnen <Martin.Honnen@xxxxxx> Date: Fri, 23 Oct 2009 14:13:28 +0200 |
Jostein Austvik Jacobsen wrote:
<xsl:template match="article"> <xsl:variable name="v1"> <xsl:copy-of select="content/node()"/> </xsl:variable>
So v1 now is a temporary document containg a deep copy of the child nodes of the content element(s). With your sample document the contents is then
<para> <note id="1">text</note> </para>
<xsl:template match="note"> The note at /article/content/para/note reads: ancestors="<xsl:value-of select="count(ancestor::*)"/>" preceding="<xsl:value-of select="count(preceding::*)"/>" contentNum="<xsl:value-of select="count(preceding::content)"/>" numberTest="<xsl:number level="any" count="content"/>" </xsl:template>
and that way the template for 'note' elements outputs
The note at /article/content/para/note reads: ancestors="1" preceding="0" contentNum="0" numberTest=""
So the template is applied to a copy of the original para element.
--
Martin Honnen http://msmvps.com/blogs/martin_honnen/
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