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[xsl] passing several external arguments to the spreadsheet

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Dear xslters,

I would like to know whether it's possible to do the following with XSLT.

I've got one XML file with one <file> element and I would like to transform it into a XML file which has several <file> elements, the only different among them being a lang attribute (the content of <file> should be the same in the input and the output). Let me show you some code and you'll see more clearly:

___intput___:
<xliff>
   <file>(...)</file>
</xliff>

___desired output___:
<xliff>
   <file lang="en">(...)</file>
   <file lang="fr">(...)</file>
   <file lang="pt">(...)</file>
</xliff>

Is it possible to pass the respective values of that attribute to the spreadsheet in some way, so that the spreadsheet will know how many (depending on the number of values) <input> elements must be generated and what value exactly their lang attribute must have. I'm wondering about how to pass the arguments to the spreadsheets and how the spreadsheets should handle them.

If this was a perl script, I would run:

$ perl -lang=en,fr,pt script.pl input.xml > output.xml

Is it possible to run something like that using the param option (or, even better, to do it in the editor)? (in capitals for clarity)

$ java -jar path/to/saxon9.jar LANG=en,fr,pt input.xml spreadsheet.xsl > output.xml

I guess it must be something like that, but then, how do I get those 3 or n parameters into the spreadsheet? If it was only one parameter i would get it with

<xsl:param name="lang"/>

but as there are more than one, I guess I should put them in a kind of array and then do a for-each?

I'd be grateful for any opinion.

Best regards!!

--
Manuel Souto Pico
Terminrleg / Responsable de servei thcnic
manuel.souto@xxxxxxxxxxxxxx <mailto:manuel.souto@xxxxxxxxxxxxxx>

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