[xsl] How to cast current-group() ?

Subject: [xsl] How to cast current-group() ?
From: Leo Studer <leo.studer@xxxxxx>
Date: Mon, 27 Apr 2009 21:39:50 +0200

Hello again

the type of current-group() and current-grouping-key() is item()* and xs:anyAtomicType?. I wonder how to cast them to what really is in them.

  <xsl:for-each-group select="/results/match" group-by="team">
    <xsl:copy-of
 select="myfn:MakeTableRow(current-grouping- key(),current-group())"/>
  </xsl:for-each-group>

In my example, the function myfh:MakeTabelRow(.,.) takes the parameters as="element(*,my:matchType)*" and as="schema- element(my:team)" respectively both complexTypes. My workaround is to leave the function parameters untyped, not really ingenious...

Thanks for your suggestions

Always
Leo

Current Thread

RE: [xsl] How to sort by elements of a function output?, (continued)
- G. Ken Holman - 24 Apr 2009 16:22:22 -0000
  - David Carlisle - 24 Apr 2009 16:26:08 -0000
  - Leo Studer - 24 Apr 2009 20:45:18 -0000
    - Leo Studer - 27 Apr 2009 19:40:28 -0000 <=
    - Michael Kay - 27 Apr 2009 20:31:18 -0000
    - Studer Leo - 28 Apr 2009 15:19:57 -0000
    - David Carlisle - 28 Apr 2009 15:34:16 -0000
    - Studer Leo - 28 Apr 2009 16:56:02 -0000

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[xsl] How to cast current-group() ?