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Hello again
the type of current-group() and current-grouping-key() is item()* and xs:anyAtomicType?. I wonder how to cast them to what really is in them.
In my example, the function myfh:MakeTabelRow(.,.) takes the parameters as="element(*,my:matchType)*" and as="schema- element(my:team)" respectively both complexTypes. My workaround is to leave the function parameters untyped, not really ingenious...
Thanks for your suggestions
[xsl] How to cast current-group() ?
Subject: [xsl] How to cast current-group() ? From: Leo Studer <leo.studer@xxxxxx> Date: Mon, 27 Apr 2009 21:39:50 +0200 |
Hello again
the type of current-group() and current-grouping-key() is item()* and xs:anyAtomicType?. I wonder how to cast them to what really is in them.
<xsl:for-each-group select="/results/match" group-by="team"> <xsl:copy-of select="myfn:MakeTableRow(current-grouping- key(),current-group())"/> </xsl:for-each-group>
In my example, the function myfh:MakeTabelRow(.,.) takes the parameters as="element(*,my:matchType)*" and as="schema- element(my:team)" respectively both complexTypes. My workaround is to leave the function parameters untyped, not really ingenious...
Thanks for your suggestions
Always Leo
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