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RE: [xsl] Getting nodes where attribute is not in list
Subject: RE: [xsl] Getting nodes where attribute is not in list From: "Bordeman, Chris" <Chris.Bordeman@xxxxxxxxxxxxxxxxx> Date: Wed, 25 Feb 2009 09:45:58 -0600 |
Thanks very much Ken. -----Original Message----- From: G. Ken Holman [mailto:gkholman@xxxxxxxxxxxxxxxxxxxx] Sent: Wednesday, February 25, 2009 9:35 AM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: Re: [xsl] Getting nodes where attribute is not in list At 2009-02-25 09:29 -0600, Bordeman, Chris wrote: >I need to do something like $items/item[Code not in $codes] where >$codes is a sequence of strings. $items/item[not(Code = $codes)] >How is this done? The "=" operator will act on a node set operand by comparing each member of the node set with the other operand. If any of the comparisons are true, the result of the comparison is true. If all of the comparisons are false, the result of the comparison is false. I hope this helps. . . . . . . . . Ken -- XQuery/XSLT training in Prague, CZ 2009-03 http://www.xmlprague.cz Training tools: Comprehensive interactive XSLT/XPath 1.0/2.0 video Video lesson: http://www.youtube.com/watch?v=PrNjJCh7Ppg&fmt=18 Video overview: http://www.youtube.com/watch?v=VTiodiij6gE&fmt=18 G. Ken Holman mailto:gkholman@xxxxxxxxxxxxxxxxxxxx Crane Softwrights Ltd. http://www.CraneSoftwrights.com/s/ Male Cancer Awareness Nov'07 http://www.CraneSoftwrights.com/s/bc Legal business disclaimers: http://www.CraneSoftwrights.com/legal
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