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--On Wednesday, February 11, 2009 09:40:48 -0500 Robert Koberg wrote:
There are XPath 2.0 functions specifically provided to do the job.
select="doc(resolve-uri(@ref,base-uri(.)))"
If you want relative references resolved as described in the W3C specifications, use these functions.
Relative reference resolution is not as simple as just replacing whatever follows the last '/'.
Re: [xsl] most efficient way to get XML source's parent dir path
Subject: Re: [xsl] most efficient way to get XML source's parent dir path From: Owen Rees <owen.rees@xxxxxx> Date: Wed, 11 Feb 2009 15:17:33 +0000 |
--On Wednesday, February 11, 2009 09:40:48 -0500 Robert Koberg wrote:
<xsl:apply-templates select="doc(concat($parent-dir, '/', @ref))/*"/>
There are XPath 2.0 functions specifically provided to do the job.
select="doc(resolve-uri(@ref,base-uri(.)))"
If you want relative references resolved as described in the W3C specifications, use these functions.
Relative reference resolution is not as simple as just replacing whatever follows the last '/'.
-- Owen Rees; speaking personally, and not on behalf of HP. ======================================================== Hewlett-Packard Limited. Registered No: 690597 England Registered Office: Cain Road, Bracknell, Berks RG12 1HN
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