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Re: [xsl] Testing for special characters

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The problem has nothing to do with special characters (At least I assume so:
it's possible that the character in question is not really "." at all, but
some other character that has not made it through to the email).

Well using this website:
http://www.pinyin.info/tools/converter/chars2uninumbers.html
It tells me that the dot you see is a "•" in "decimal (not hex) form of Unicode numerical character references (NCRs)". If you go to Google and search for that code it will return the character.

When I used that in the test:
<xsl:template match="P">
   <xsl:if test=".='&#8226; '">
       <xsl:value-of select="current()" />
   </xsl:if>
</xsl:template>

It picks up the bullet points no problem. I am still having difficulty selecting the previous node. So far I have thisL
<xsl:value-of select="preceding-sibling::Child[1]" />
But it doesn't work.

Any ideas what I am doing wrong.
Thanks,
Graeme

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From: "Michael Kay" <mike@xxxxxxxxxxxx>
Sent: Friday, January 02, 2009 3:03 PM
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Subject: RE: [xsl] Testing for special characters

Your test:

<xsl:if test="P='. '">

tests whether any child::P of the context node is equal to ". ". This isn't
very useful if you are positioned on the <Sect> element, and it isn't at all
useful if you are positioned on the "P" element. The most likely explanation
is that you are using this test "in the wrong place".

The problem has nothing to do with special characters (At least I assume so:
it's possible that the character in question is not really "." at all, but
some other character that has not made it through to the email).

It's hard to propose a solution without seeing a wider selection of the
possible inputs that need to be processed.

Michael Kay
http://www.saxonica.com/

-----Original Message-----
From: Graeme Kidd [mailto:coolkidd3@xxxxxxxxxxx]
Sent: 02 January 2009 14:36
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: [xsl] Testing for special characters

Hi,
I have used  Adobe Acrobat to export a PDF as XML and I am
wanting to convert it.
Sometime it displays an unordered list like this:

<Sect>
    <P>List: </P>
    <P>Item 1; </P>
    <P>. </P>
    <P>Item 2; </P>
    <P>. </P>
    <P>Item 3; </P>
    <P>. </P>
</Sect>

Which I am trying to convert to this:

<Sect>
    <P>List:</P>
    <UL>
        <LI>Item 1; </LI>
        <LI>Item 2; </LI>
        <LI>Item 3; </LI>
    </UL>
</Sect>

The best I can think of is to check if there is a bullet
point then use the previous <P> node.  At the moment I am
having trouble just checking if there is a bullet point as
this doesn't seem to work:
<xsl:if test="P='. '">

I am thinking it might be because it is a special character.
I have tried specifying the output as UTF-8 <xsl:output
method="xml" indent="yes" encoding="UTF-8" />

But that didn't seem to help, so does anyone else have any ideas?
Thanks

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