[XSL-LIST Mailing List Archive Home]
[By Thread]
[By Date]
Re: [xsl] calculating relative position in document order
Subject: Re: [xsl] calculating relative position in document order From: "Darcy Parker" <darcyparker@xxxxxxxxx> Date: Thu, 16 Oct 2008 14:15:06 -0400 |
Hi Tom, (Earlier today Michael Kay answered a message that involved recommending this library: http://www.functx.com/functx/ ... so I had a quick look at functx and it is fresh in my mind.) These functions are not exactly like your fantasy pseudo code... but I think there some useful functions that may have help solve your problem.... For example: http://www.xsltfunctions.com/xsl/functx_sequence-node-equal.html http://www.xsltfunctions.com/xsl/functx_sequence-node-equal-any-order.html If you peruse the functions, I think you'll find many other interesting/related functions that you may be able to leverage. (Note: I found the download link difficult to find on the page... Hint: It's at the top of the page.) Darcy On Thu, Oct 16, 2008 at 12:53 PM, tom s <tshmit@xxxxxxxxx> wrote: > Hi, > > I'd like to be able to determine which element is "closer", in terms of document order, to a given element. eg, given two structures containing siblings: > > <a> > <b> > <c> > and > <b> > <a> > <c> > > I'd like to detect that the second structure is "out of order". In my fantasy pseudo code, I might express the constraint as: > > //c[positionEX(preceding::a[1]) > positionEX(preceding::b[1])] > > Where my fantasy positionEX() function returns the absolute position of the argument in the document. > > Am I missing something, or is implementing this operation in real xpath/xslt much more difficult than it seems it should be? > > Thanks in advance for any help... > > --T
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
Re: [xsl] calculating relative posi, G. Ken Holman | Thread | Re: [xsl] calculating relative posi, tom s |
Re: [xsl] calculating relative posi, tom s | Date | Re: [xsl] Expensive XSLT2 - suggest, Michael Müller-Hille |
Month |