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Re: [xsl] determine maximum columns in table

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At 2008-10-08 13:20 +1300, Trevor Nicholls wrote:

 <!-- output maximum number of columns in any child row -->
 <xsl:template name="counttablecols">
  <xsl:for-each select="*/tr">
   <xsl:sort select="count(td)" order="descending" />
   <xsl:if test="position() = 1">
    <xsl:value-of select="count(td)" />
   </xsl:if>
  </xsl:for-each>
 </xsl:template>

I can't see how to modify the sort so that I count 1 for each non-colspanned
td and the appropriate value for each td which does have a colspan
attribute. Is it possible?

Just in the very way you said it:

count(td[not(@colspan)]) + sum(td/@colspan)

Consider the following:

  <td/>
  <td colspan="3"/>
  <td/>
  <td/>
  <td colspan="2"/>
  <td colspan="3"/>
  <td/>

This is 4 + ( 3 + 2 + 3 ) = 12

I hope this helps.

. . . . . . . . . . Ken

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