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Hi,
You can use xs:for-each-group. For example if you join the tag ids as the grouping key then you will get a stylesheet like below:
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="doc">
<xsl:for-each-group select="odo" group-by="string-join(tag/@id, '-')">
<xsl:copy-of select="."/>
</xsl:for-each-group>
</xsl:template>
</xsl:stylesheet>
Kolda, Marcin wrote:
Re: [xsl] Removing duplicates based on set of identifiers
Subject: Re: [xsl] Removing duplicates based on set of identifiers From: George Cristian Bina <george@xxxxxxxxxxxxx> Date: Mon, 15 Sep 2008 11:31:42 +0300 |
Hi,
You can use xs:for-each-group. For example if you join the tag ids as the grouping key then you will get a stylesheet like below:
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="doc">
<xsl:for-each-group select="odo" group-by="string-join(tag/@id, '-')">
<xsl:copy-of select="."/>
</xsl:for-each-group>
</xsl:template>
</xsl:stylesheet>
Best Regards, George -- George Cristian Bina <oXygen/> XML Editor, Schema Editor and XSLT Editor/Debugger http://www.oxygenxml.com
Kolda, Marcin wrote:
Hi,
I have problem with removing group duplicates. I want to remove duplicates, which contains childs with identical ids. I'm looking for solution that does that using XSLT 2.0. Example of input and output is below.
Input: <doc> <odo> <tag id="1"/> <tag id="2"/> <tag id="3"/> </odo> <odo> <tag id="1"/> <tag id="3"/> </odo> <odo> <tag id="2"/> <tag id="3"/> </odo> <odo> <tag id="1"/> <tag id="2"/> <tag id="3"/> </odo> <odo> <tag id="1"/> <tag id="3"/> </odo> <odo> <tag id="3"/> </odo> </doc>
Output: <doc> <odo> <tag id="1"/> <tag id="2"/> <tag id="3"/> </odo> <odo> <tag id="1"/> <tag id="3"/> </odo> <odo> <tag id="2"/> <tag id="3"/> </odo> <odo> <tag id="3"/> </odo> </doc>
Do you have any ideas?
Marcin
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