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Re: [xsl] (simple?) xpath question
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Subject: Re: [xsl] (simple?) xpath question From: Colin Paul Adams <colin@xxxxxxxxxxxxxxxxxx> Date: Fri, 29 Aug 2008 20:22:45 +0100 |
>>>>> "Mark" == mark bordelon <markcbordelon@xxxxxxxxx> writes:
Mark> All *help*! What is the best way to query xml with xpath
Mark> to get a disjoint nodelist? Specifically i want to include
Mark> just the root node alongwith a descendent node. XML:
Mark> <a> <b> <c> </c> </b> </a> XPATH: //c
Mark> DESIRED RESULT NODELIST: i.e. not this: <c> </c> but
Mark> rather this: <a> <c> </c> </a>
One possibility is:
//*[name() != "b"]
It depends on your exact requirements.
--
Colin Adams
Preston Lancashire
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