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Re: [xsl] What's wrong with my Xpath declaration?
Subject: Re: [xsl] What's wrong with my Xpath declaration? From: "Mandar Jagtap" <mandar.jagtap@xxxxxxxxx> Date: Tue, 15 Jul 2008 16:52:55 +0530 |
It may be the string() function. Try using only . instead of string() in case of <xsl:when test...> and remove the '/string()' completely in case of <xsl:value-of..... Thanks & Regards Mandar On 7/15/08, Pankaj Chaturvedi <pankaj.chaturvedi@xxxxxxxxx> wrote: > > > Mandar wrote: > > I would have done this as following: > > <xsl:for-each select="./author[1]/name/givenname"> > <xsl:choose> > <xsl:when test="contains(., '.')"> > <xsl:value-of select="."/> > </xsl:when> > <xsl:otherwise> > <xsl:value-of select="substring(., 1, 1)"/> > <xsl:text>.</xsl:text> > </xsl:otherwise> > </xsl:choose> > </xsl:for-each> > > Let me know if it works. > > > It works but what's wrong with my template rule? I am sure my Xpath > declaration is not correct. > > > > > > > > > Best, > > > > Pankaj Chaturvedi > > > > ====================================================================== > > ====== > > ================ > > > > > > Confidentiality Notice:" This message and any attachment(s) contained > > here are information that is confidential, proprietary to IDS Infotech > > Ltd. and its customers. > > Contents may be privileged or otherwise protected by law. The > > information is solely intended for the individual or the entity it is > > addressed to. If you are not the intended recipient of this message, > > you are not authorized to read, forward, print, retain, copy or > > disseminate this message or any part of it. If you have received this > > e-mail in error, please notify the sender immediately by return e-mail > > and delete it from your computer." > > > > > > > -- > Thanks & Regards, > Mandar > > -- Thanks & Regards, Mandar
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