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RE: [xsl] What's wrong with my Xpath declaration?
Subject: RE: [xsl] What's wrong with my Xpath declaration? From: "Pankaj Chaturvedi" <pankaj.chaturvedi@xxxxxxxxx> Date: Tue, 15 Jul 2008 16:39:50 +0530 |
Mandar wrote: I would have done this as following: <xsl:for-each select="./author[1]/name/givenname"> <xsl:choose> <xsl:when test="contains(., '.')"> <xsl:value-of select="."/> </xsl:when> <xsl:otherwise> <xsl:value-of select="substring(., 1, 1)"/> <xsl:text>.</xsl:text> </xsl:otherwise> </xsl:choose> </xsl:for-each> Let me know if it works. It works but what's wrong with my template rule? I am sure my Xpath declaration is not correct. > > > Best, > > Pankaj Chaturvedi > > ====================================================================== > ====== > ================ > > > Confidentiality Notice:" This message and any attachment(s) contained > here are information that is confidential, proprietary to IDS Infotech > Ltd. and its customers. > Contents may be privileged or otherwise protected by law. The > information is solely intended for the individual or the entity it is > addressed to. If you are not the intended recipient of this message, > you are not authorized to read, forward, print, retain, copy or > disseminate this message or any part of it. If you have received this > e-mail in error, please notify the sender immediately by return e-mail > and delete it from your computer." > > -- Thanks & Regards, Mandar
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