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Subject: [xsl] XPath and noname namespace From: "Adam Komisarek" <akakus@xxxxxxxxx> Date: Mon, 14 Jul 2008 16:52:08 +0200 |
Hello! I have found workaround but I wonder why it must be done in that way.. Is it some kind of bug in XPath? I have simple document:<svg xmlns="http://www.w3.org/2000/svg"> <a>aadsf</a> </svg> And now "//a" doesn't find a node.. I must use //*[local-name() = 'a'], but funny thing is that //*[name() = 'a'] works as well.. Why is that? Thanks, Adam
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| [xsl] Re: xsl-list Digest 9 Jul 200, Krishnaiah Korrapati | Thread | Re: [xsl] XPath and noname namespac, G. Ken Holman |
| [xsl] Re: xsl-list Digest 9 Jul 200, Krishnaiah Korrapati | Date | [xsl] Content negotiation in XSLT, Richard Light |
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