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Re: [xsl] Making all attributes empty and retaining the attributes names

Subject: Re: [xsl] Making all attributes empty and retaining the attributes names
From: Martin Honnen <Martin.Honnen@xxxxxx>
Date: Fri, 30 May 2008 15:02:41 +0200

Pankaj Chaturvedi wrote:

I've also tried it prior. But doesn't seems to be working.

   <xsl:template match="@*">
     <xsl:attribute name="{name()}"/>
   </xsl:template>

I think that template is fine for doing what you want (copying attributes with their names but with empty values), now you also need to make sure you process attribute nodes e.g. <xsl:template match="*"> <xsl:copy> <xsl:apply-templates select="@* | node()"/> </xsl:copy> </xsl:template>

--

	Martin Honnen
	http://JavaScript.FAQTs.com/

Current Thread
Re: [xsl] Making all attributes empty and retaining the attributes names, (continued) Martin Honnen - 30 May 2008 12:22:57 -0000 Pankaj Chaturvedi - 30 May 2008 12:58:19 -0000 David Carlisle - 30 May 2008 13:00:26 -0000 Pankaj Chaturvedi - 30 May 2008 13:09:41 -0000 Martin Honnen - 30 May 2008 13:03:48 -0000 <=

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