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Re: [xsl] Combine two diff xmls - Sorting by date

Subject: Re: [xsl] Combine two diff xmls - Sorting by date
From: Martin Honnen <Martin.Honnen@xxxxxx>
Date: Thu, 29 May 2008 13:25:26 +0200

sudheshna iyer wrote:

From xsl of File2.xml:

	 <xsl:apply-templates select="* |
document('File3.xml')/*"/>  ==> IS THIS CORRECT?
Step3: Now File2Xsl contains File2.xml and File3.xml

Step4: But when I process combined XML, each XML is
getting processed as two files. I
am not seeing one x

I think you should be able to do <xsl:apply-templates select="/Announcements/announcement | document('File3.xml')/Annoucements/announcement"> <xsl:sort select="translate(anc_date, '-', '')" data-type="number" order="descending"/> </xsl:apply-templates>

--

	Martin Honnen
	http://JavaScript.FAQTs.com/

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Re: [xsl] Sorting by date, (continued)

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Re: [xsl] Combine two diff xmls - , sudheshna iyer	Thread	Re: [xsl] Combine two diff xmls - , Martin Honnen
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