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Re: [xsl] method transform (JAXP)
Subject: Re: [xsl] method transform (JAXP) From: "Mukul Gandhi" <gandhi.mukul@xxxxxxxxx> Date: Thu, 8 May 2008 17:29:36 +0530 |
After quickly looking at the Java APIs, following comes to my mind: StringWriter sw = new StringWriter(); StreamResult sr = new StreamResult(sw); transformer.transform(new StreamSource(sourceId), sr); StringBuffer sb = sr.getBuffer(); This has not been tested. On 5/8/08, IZASKUN GUTIERREZ GUTIERREZ <igutierrez027@xxxxxxxxxxxxx> wrote: > Hello everybody! > > I am using JAXP to execute templates.In the method transformer.transform , > the > > second parameter is one StreamResult. I can obtain the result in a File like > > this: > > > File output = new File > ("C:/Users/Izaskun/Desktop/workspace5/modelo/mayo.txt"); > transformer.transform(new StreamSource(sourceId), new StreamResult(output)); > > > I need to obtain the result in a var String because the result is only one > line > > and I dont know how to do it, because I tried a lot of forms but I dont > obtain > > this. > > Could anybody help me? > > Regards, > > Izaskun -- Regards, Mukul Gandhi
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