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Re: [xsl] How to sort a nodeset returned by key()?
Subject: Re: [xsl] How to sort a nodeset returned by key()? From: David Carlisle <davidc@xxxxxxxxx> Date: Tue, 8 Apr 2008 23:28:09 +0100 |
> Here is the missing code : ah, which is more or less the same as I came up with, modulo a few variables, The xslt2 solution, using xsl:for-each-group, would be essentially identical to this just doing a straight translation of <xsl:for-each select="salesman/account[count( . |... to xsl:for-each-grouo, and <xsl:for-each select="key('accounts-by-region', $region)"> to <xsl:for-each select="current-group()" so it's a fair bit more readable but structurally identical. David
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