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RE: [xsl] Slow XSLT
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Subject: RE: [xsl] Slow XSLT From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Wed, 12 Mar 2008 23:52:00 -0000 |
> It is like if I was using [1], [2] to get the current Row > (Row[1], Row[2]) but the '.' does not work with the node set $set > > Is that clearer? No, I'm sorry, it isn't. Either you want to process the current row, or you want to process the rows in $set - you keep talking about the "current" Row, and then saying you don't want the current Row, you want a row in $set. You can do either, but you seem to be confused about which you want. Michael Kay http://www.saxonica.com/
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