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RE: [xsl] Slow XSLT

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Hi Michael,

Thanks for your reply.

--- Michael Kay <mike@xxxxxxxxxxxx> wrote:

> But I can't relate that to your next statement of
> the problem
> What does "that" refer to - the current Row, or the
> child of the current
> Row?

The current Row can have 2, 3, 4 and more Cell child
elements. Therefore if the current Row in the node set
has 2 Cell elemets then I nedd to apply

current Row/Cell (the count of Cell child of current
Row node is 2)

Next time if the current Row has 3 Cell elements then

currrent Row/Cell (the count of Cell child of current
row = 3

It is like if I was using [1], [2] to get the current
Row (Row[1], Row[2]) but the '.' does not work with
the node set $set

Is that clearer?

Cheers

C



> > 
> > <xsl:apply-templates select="$set[postion()]/*"/>
> 
> My first guess would be that you want
> 
> <xsl:variable name="p" select="position()"/>
> <xsl:apply-templates select="$set[$p]"/>
> 
> Note that position() changes inside a predicate, and
> that [position()] means
> [position()=position()] which is obvious nonsense.
> 
> But I can't relate that to your next statement of
> the problem
> > 
> > I need to apply templates to the child of the
> current Row 
> > element that is in the $set node set. 
> 
> What does "that" refer to - the current Row, or the
> child of the current
> Row?
> > 
> > How do I get the current context using a node set
> variable?
> > 
> 
> You don't. You either use the current context or you
> use a variable. The
> value of a variable is independent of the current
> context - that's one of
> the things that makes it useful.
> 
> Michael Kay
> http://www.saxonica.com/
> 
> 



		
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