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Re: [xsl] xalan and replace "regex"

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also check out:
http://xml.apache.org/xalan-j/extensionslib.html#exslt
http://www.exslt.org for examples

Mansour wrote:
> Hello:
> Is there any way I can use replace with xalan. I have tried every
> thing possible but couldn't get it to work:
>
> <?xml version="1.0" encoding="UTF-8" ?>
> <xsl:stylesheet version="2.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
> xmlns:xalan="http://xml.apache.org/xalan"
> xmlns:str="http://exslt.org/strings">
>    <xsl:import href="str/str.xsl" />
>      <xsl:template match="program">
>        <xsl:value-of select="replace(.,'public','&lt;KeyWord&gt; pulic
> &lt;/KeyWord&gt;')" />
>    </xsl:template>
> </xsl:stylesheet>
>
>
>
>
> I need to scan a piece of java code and be able to highlight the words
> based on their meaning. Anyone had luck with xalan regex ??  or
> analyze-string ??

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