Re: [xsl] xalan and replace "regex"

Subject: Re: [xsl] xalan and replace "regex"
From: Mansour <mansour77@xxxxxxxxx>
Date: Thu, 27 Dec 2007 10:09:48 -0400

I don't know if this would be a good idea at this point.

Michael Kay wrote:

Is there any way I can use replace with xalan.


The replace() function is new in XSLT 2.0, and Xalan only supports XSLT 1.0.
Switch to Saxon.

Michael Kay
http://www.saxonica.com/

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[xsl] xalan and replace "regex" Mansour - Thu, 27 Dec 2007 05:02:40 -0400 Colin Paul Adams - Thu, 27 Dec 2007 09:10:37 +0000 Michael Kay - Thu, 27 Dec 2007 10:54:46 -0000 Mansour - Thu, 27 Dec 2007 10:09:48 -0400 <= Abel Braaksma - Thu, 27 Dec 2007 15:15:11 +0100 Mansour - Thu, 27 Dec 2007 10:20:25 -0400 Abel Braaksma - Thu, 27 Dec 2007 15:29:22 +0100 Mansour - Thu, 27 Dec 2007 11:43:11 -0400

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