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RE: [xsl] xalan and replace "regex"

Subject: RE: [xsl] xalan and replace "regex"
From: "Michael Kay" <mike@xxxxxxxxxxxx>
Date: Thu, 27 Dec 2007 10:54:46 -0000

> Is there any way I can use replace with xalan. 

The replace() function is new in XSLT 2.0, and Xalan only supports XSLT 1.0.
Switch to Saxon.

Michael Kay
http://www.saxonica.com/

Current Thread
[xsl] xalan and replace "regex" Mansour - 27 Dec 2007 09:03:05 -0000 Colin Paul Adams - 27 Dec 2007 09:11:04 -0000 Michael Kay - 27 Dec 2007 10:55:17 -0000 <= Mansour - 27 Dec 2007 14:10:22 -0000 Abel Braaksma - 27 Dec 2007 14:15:32 -0000 Mansour - 27 Dec 2007 14:21:04 -0000 Abel Braaksma - 27 Dec 2007 14:29:31 -0000

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