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Re: [xsl] xalan and replace "regex"

Subject: Re: [xsl] xalan and replace "regex"
From: Colin Paul Adams <colin@xxxxxxxxxxxxxxxxxx>
Date: Thu, 27 Dec 2007 09:10:37 +0000

>>>>> "Mansour" == Mansour  <mansour77@xxxxxxxxx> writes:

    Mansour> Hello: Is there any way I can use replace with xalan. I
    Mansour> have tried every thing possible but couldn't get it to
    Mansour> work:

No. It's not an XSLT 2.0 processor.
-- 
Colin Adams
Preston Lancashire

Current Thread
[xsl] xalan and replace "regex" Mansour - 27 Dec 2007 09:03:05 -0000 Colin Paul Adams - 27 Dec 2007 09:11:04 -0000 <= Michael Kay - 27 Dec 2007 10:55:17 -0000 Mansour - 27 Dec 2007 14:10:22 -0000 Abel Braaksma - 27 Dec 2007 14:15:32 -0000 Mansour - 27 Dec 2007 14:21:04 -0000

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