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[xsl] xalan and replace "regex"

Subject: [xsl] xalan and replace "regex"
From: Mansour <mansour77@xxxxxxxxx>
Date: Thu, 27 Dec 2007 05:02:40 -0400

Hello: Is there any way I can use replace with xalan. I have tried every thing possible but couldn't get it to work:

<?xml version="1.0" encoding="UTF-8" ?> <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xalan="http://xml.apache.org/xalan" xmlns:str="http://exslt.org/strings"> <xsl:import href="str/str.xsl" /> <xsl:template match="program"> <xsl:value-of select="replace(.,'public','<KeyWord> pulic </KeyWord>')" /> </xsl:template> </xsl:stylesheet>

I need to scan a piece of java code and be able to highlight the words based on their meaning. Anyone had luck with xalan regex ?? or analyze-string ??

Current Thread
[xsl] xalan and replace "regex" Mansour - 27 Dec 2007 09:03:05 -0000 <= Colin Paul Adams - 27 Dec 2007 09:11:04 -0000 Michael Kay - 27 Dec 2007 10:55:17 -0000 Mansour - 27 Dec 2007 14:10:22 -0000 Abel Braaksma - 27 Dec 2007 14:15:32 -0000

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