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Re: [xsl] How to use the same expression in a match and a select test
Subject: Re: [xsl] How to use the same expression in a match and a select test From: David Carlisle <davidc@xxxxxxxxx> Date: Mon, 3 Dec 2007 14:02:05 GMT |
> Not with a variable, but you can use a predicate function. yes or, in xslt 1 an entity http://www.biglist.com/lists/xsl-list/archives/200711/msg00542.html One use I have seen for entities in XSLT1 is as a proxy for function definitions. Rather than having entities for xpath literals as in teh examples here you can have an entity that expands to a boolean predicate which you use as foo[&bar;] with teh predicate being evaluated each time. Again though in xslt2 you can just parse the predicate once by making it a function accessed like foo[my:bar(.)] which is often nicer than using entity expansion. or a key or as I said, for xslt2 in the actual problem, at hand I'd use for-each-group http://lists.mulberrytech.com/xsl-list/archives/ David ________________________________________________________________________ The Numerical Algorithms Group Ltd is a company registered in England and Wales with company number 1249803. The registered office is: Wilkinson House, Jordan Hill Road, Oxford OX2 8DR, United Kingdom. This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. ________________________________________________________________________
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