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Re: [xsl] Using a sequence of years to select documents to display in a table row
Subject: Re: [xsl] Using a sequence of years to select documents to display in a table row From: "Michael Tracey Zellmann" <tracey.zellmann@xxxxxxxxx> Date: Fri, 23 Nov 2007 17:36:48 -0500 |
Thanks you both ! Worked well and that is much cleaner. On Nov 23, 2007 5:02 PM, Michael Kay <mike@xxxxxxxxxxxx> wrote: > > > > <xsl:variable name="docs" select="documents/document"/> > > <xsl:for-each select="1842 to 1862"> > > <tr><td><xsl:value-of select="."/></td> > > <td> > > <xsl:apply-templates select="$docs[year = . and > > contains(title, 'Selectmen')"/> > > I suspect this should be > > <xsl:apply-templates select="$docs[year = current() and contains(title, > 'Selectmen')"/> > > Michael Kay > http://www.saxonica.com/
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