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RE: [xsl] Find the node with maximum elements
I agree - a nice solution.
But the solution would be even nicer if we had more access to the key.
Once we have the key we can select all elements that have 0 cars, or 1 car, or
6 cars, but not a run-time function of the key use value such as what we want:
the largest value of 'use' in this document. So we do what is shown below -
scan through the elements to find the maximum value even though the
information is _already in the key_. (I doubt that I have the terminology
I would like something like:
<xsl:for-each select="key('cars', max())">
<xsl:for-each select="key('cars', sort(ascending))">
or if 'use' is alpha, something like:
<xsl:for-each select="key('carnames', not(contains('xyz'))">
Is this a good addition for XSLT 2.1? It seems to me this allows both
simplified and more efficient code.
From: Mukul Gandhi [mailto:gandhi.mukul@xxxxxxxxx]
Sent: November 5, 2007 1:02 PM
Subject: Re: [xsl] Find the node with maximum elements
Nice solution, Scott.
On 11/5/07, Scott Trenda <Scott.Trenda@xxxxxxxx> wrote:
> This may be better represented with 2.0's grouping facilities, but
> here's the 1.0 solution I'd use to alleviate Mukul's concerns
> (building off Michael's response with <xsl:sort/>):
> <xsl:stylesheet version="1.0"
> <xsl:key name="cars" match="*[Car]" use="count(Car)"/>
> <xsl:template match="Sample">
> <xsl:variable name="max-cars">
> <xsl:for-each select=".//*[Car]">
> <xsl:sort select="count(Car)" data-type="number"/>
> <xsl:if test="position() = last()">
> <xsl:value-of select="count(Car)"/>
> <xsl:for-each select="key('cars', $max-cars)">
> <!-- do whatever you'd do with the results here -->
> <xsl:value-of select="name()"/>
> ~ Scott