[xsl] normalize-space processing all nodes hack?

 Hi!

 I'd like to fill variable textOnly by normalized string of all text of the
element A. I'm just wondering is there any way, I could write it as one XPath
expression, like:

 <xsl:variable name="textOnly" select="normalize-space(A//text())"/>

(but here only the first text node is used)?

 Please note, I'm interested only in the "one XPath expression" way, I know
how solve problem in different way*.

 Thanks, Tomas

*like:

<xsl:variable name="textOnlyPre">
     <xsl:copy-of select="A//text()">
</xsl:variable>
<xsl:variable name="textOnly" select="normalize-space($textOnlyPre)"/>